Problem Statement 6 : Write an extension of “sequence” to remove duplicates from it, provided order of elements would not get change.
Solution : In case of duplicates first thought comes in mind is of “Set”, as set can remove duplicates. But here we also need to maintain ordering of elements🤔. Interestingly still we are going to make use of “Set” but in a smarter way 😎. Code 👇
Problem Statement 7: Find a pair of elements from an array whose sum equals a given number.
Input : Arr = [2,3,5,4,1,7,6,8,9,5,3,3,3,3,3,3,3,3,3], sum = 14
Output : [(8,6),(9,5)] // Array of tuples having sum equal to 14
Solution : Simple solution could be using two “for loops”, but its time complexity turns out to be O(n²), not good enough huh! 🤔 . Can we solve it in O(n) 🤔? Off course we can, “Where there is a will, there is a way 😀”. We are going to use hash 👇
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